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kolbaska11 [484]
4 years ago
7

At the market,

Mathematics
2 answers:
Strike441 [17]4 years ago
8 0

Answer:

6 batteries cost $7.5

Step-by-step explanation:

8 batteries = $10  

6 batteries = x

x = cost of 6 batters in dollars

Step: cross multiply

8x = 10*6

x = 60/8

x = 7.5

ch4aika [34]4 years ago
4 0

Answer:

7.5

Step-by-step explanation:

You divide the number with another and multiply than u got it.

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HELPPP PLEASEEEE<br> enter the value that makes the equation 1/4(12x-8)+2x=-17
Alchen [17]

Answer:

x = -3

Step-by-step explanation:

1/4(12x - 8) + 2x = -17

3x - 2 + 2x = -17

3x + 2x = -17 + 2

5x = -15

5x ÷ 5 = -15 ÷ 5

x = -3

8 0
3 years ago
19pi/11 is coterminal with
Margaret [11]
If the pi = 3.14
then the answer is ≈5.42
5 0
3 years ago
There's a photo about it I absolutely know nothing about this question and I really need help​
aniked [119]
It’s D
(It’s making me write more words)

4 0
3 years ago
The value of a book is $150 and decreases at a rate of 4% per year. Find the value of the book after 12 years
nevsk [136]
If it decreases at 4% every year, then its value becomes:

100% - 4% = 96% = 96/100 = 0.96

At the end of the 1 year its value becomes:  150*(0.96)

At the end of the 2 years its value becomes:  150*(0.96)*(0.96) = 150*(0.96)²

At the end of the 3 years its value becomes:  150*(0.96)*(0.96)*(0.96) = 150(0.96)³

So similarly at the end of 12 years, its value becomes 150*(0.96)¹²

=50*(0.96)¹²    simplify with calculator.

<span>≈ 91.91

Value at the end of 12 years becomes ≈ $</span><span>91.91

I hope this helps.
</span>
8 0
3 years ago
A study reveals that 65% of homeowners in Omaha own a lawn mower. To test this claim, you form a sample of 500 homeowners in Oma
kotegsom [21]

Answer:

There is no enough evidence to reject the claim using a level of significance of 5%

Step-by-step explanation:

Let p be the true proportion of homeowners in Omaha who own a lawnmower. We want to test  

H_{0}: p = p_{0} = 0.65 vs H_{1}: p\neq 0.65 (two-tailed alternative).

We have a large sample of size n = 500 and a point estimate for p is \hat{p}=0.68. The test statistic is given by

Z=\frac{\hat{p}-p_{0}}{\sqrt{p_{0}(1-p_{0})/n}}=\frac{0.68-0.65}{\sqrt{0.65(1-0.65)/500}} where \sqrt{0.65(1-0.65)/500} is the standard error of \hat{p} when H_{0} is true. The observed value is z_{0} = 1.4064 which comes from a standard normal distribution. Because we want to use a level of significance of 5%, our rejection region is RR={z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles respectively. Because 1.4064 does not belong to RR, we fail to reject the null hypothesis.

6 0
3 years ago
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