Answer:
Step-by-step explanation:
From the graph attached,
Coordinates of the vertices are,
Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)
Following the rule of translation by 3 units to the right and 2 units down 
(x, y) → (x+3, y-2)
Q(1, 3) → Q''(4, 1)
R(3, -3) → R"(6, -5)
S(0, -2) → S"(3, -4)
T(-2, 1) → T"(1, -1)
Following rule 
(rotation of a point by 180° about the origin) will give the image points,
(x, y) → (-x, -y)
Q"(4, 1) → Q'(-4, -1)
R"(6, -5) → R'(-6, 5)
S"(3, -4) → S'(-3, 4)
T"(1, -1) → T'(-1, 1)
Answer:
m(arc ZWY) = 305°
Step-by-step explanation:
8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,
Angle formed by two tangents = 
= 
= 
= 40°
9). Following the same rule as above,
Angle formed between two tangents =
125 = ![\frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Bmajor%20arc%7D%29-m%28%5Ctext%7Bminor%20arc%7D%29%5D)
250 = ![[m(\text{arc ZWY})-m(\text{arc ZY})]](https://tex.z-dn.net/?f=%5Bm%28%5Ctext%7Barc%20ZWY%7D%29-m%28%5Ctext%7Barc%20ZY%7D%29%5D)
250 = m(arc ZWY) - 55
m(arc ZWY) = 305°
Therefore, measure of arc ZWY = 305° will be the answer.
10). m(arc BAC) = ![\frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Bm%28%5Ctext%7Barc%20BDC%7D%29-m%28%5Ctext%7Barc%20BC%7D%29%5D%29)
= 
= 
= 74°
I believe it would be 1 aka F
Answer:
17
Step-by-step explanation:
Number of students in soccer club, n(S) = 50
Number of students in Art club, n(A) = 53
Number of students in Gaming club, n(G)
n(
) = 100
n(
) = 9
n(
) = 20
n(
) = 35
n(
) = 29
Formula:
n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )
Putting the values:
100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9
100 = 112 + n(G) - 84
n(G) = 72
Number of students in gaming club only = n(G) - n() - n() + n()
= 72 - 35 - 29 + 9
= <em>17</em>
767,074 rounded to the nearest hundred thousand is 800,000.
