Please help me with this problem aspa
1 answer:
Answer:
See below and attached picture
Step-by-step explanation:
a. To graph the equation set y = 0 and solve for t.
y = -16t² + 100
0 = -16t² + 100
100 = -16t²
6.25 = t²
+/- 2.5 = t
Mark the points (-2.5,0) and (2.5,0). Then mark the highest point at (0,100). Draw a curve or parabola to connect the points.
b. Domain is the set of t values. This is the time it's in the air. The graph shows it at height 100 at t = 0 and at height 0 at t = 2.5. The domain is [0, 2.5].
Range is the set of y values. This is the height of the object. The graph shows it at height 100 at the beginning and then falls to height 0. The range is [0,100].
c. The graph has the point (1,84). This means it was at height 84 feet at 1 second.
d. The graph has a point about (1.75, 50). This means at about 50 feet it was 1.75 seconds.
e. The shingle is at height 0 feet at 2.5 seconds when it crosses the x-axis.
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In order to make a frequency plot first we need to find the proportion of each outcome.
Total number of results = 15+20+5+5+5 = 50
Frequency of 0 = 15
Proportion of 0 = 15/50 = 0.3
Frequency of 1 = 20
Proportion of 0 = 20/50 = 0.4
Frequency of 2 = 5
Proportion of 2 = 5/50 = 0.1
Frequency of 3 = 5
Proportion of 3 = 5/50 = 0.1
Frequency of 4 = 5
Proportion of 4 = 5/50 = 0.1
Now we need to plot the data on a frequency plot. The x-axis shows the outcomes from 0 to 4 and y-axis shows the frequency of each outcomes. The frequency plot is shown in the figure attached with.
Total number of results = 15+20+5+5+5 = 50
Frequency of 0 = 15
Proportion of 0 = 15/50 = 0.3
Frequency of 1 = 20
Proportion of 0 = 20/50 = 0.4
Frequency of 2 = 5
Proportion of 2 = 5/50 = 0.1
Frequency of 3 = 5
Proportion of 3 = 5/50 = 0.1
Frequency of 4 = 5
Proportion of 4 = 5/50 = 0.1
Now we need to plot the data on a frequency plot. The x-axis shows the outcomes from 0 to 4 and y-axis shows the frequency of each outcomes. The frequency plot is shown in the figure attached with.