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Likurg_2 [28]
3 years ago
9

Please help me with this problem aspa

Mathematics
1 answer:
Flura [38]3 years ago
4 0

Answer:

See below and attached picture

Step-by-step explanation:

a. To graph the equation set y = 0 and solve for t.

y = -16t² + 100

0 = -16t² + 100

100 = -16t²

6.25 = t²

+/- 2.5 = t

Mark the points (-2.5,0) and (2.5,0). Then mark the highest point at (0,100). Draw a curve or parabola to connect the points.

b. Domain is the set of t values. This is the time it's in the air. The graph shows it at height 100 at t = 0 and at height 0 at t = 2.5. The domain is [0, 2.5].

Range is the set of y values. This is the height of the object. The graph shows it at height 100 at the beginning and then falls to height 0. The range is [0,100].

c. The graph has the point (1,84). This means it was at height 84 feet at 1 second.

d. The graph has a point about (1.75, 50). This means at about 50 feet it was 1.75 seconds.

e. The shingle is at height 0 feet at 2.5 seconds when it crosses the x-axis.

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the sum of two numbers is 57. if the larger of the two numbers is 9 less than twice the smaller, find the two numbers
svp [43]

Answer:

The answer is 35 and 22

Because:

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7 0
3 years ago
Suppose you are making granola bars with 3 cups of oats. How much quinoa, flaxseed, and soy protein would you use would you need
Andreas93 [3]

Answer: \frac{3}{4}\ cup of quinoa, \frac{3}{8}\ cup of flaxseed, 1\ cup of soy protein.

Step-by-step explanation:

<h3> The missing table is attached.</h3>

Let be "q" the amount of cups of quinoa you'd need to use making the granolas with 3 cups of oats.

Based on the table you can write the following proportion:

\frac{\frac{1}{2} }{2}=\frac{q}{3}

Solving for "q", you get:

\frac{1}{4}=\frac{q}{3}\\\\q=\frac{3}{4}

 Let be "f" the amount of cups of flaxseed you'd need to use making the granolas with 3 cups of oats.

With the data given in the table you can write the following proportion:

\frac{\frac{1}{4} }{2}=\frac{f}{3}

Solving for "f", you get:

\frac{1}{8}=\frac{f}{3}\\\\f=\frac{3}{8}

Let be "s" the amount of cups of soy protein you'd need to use making the granolas with 3 cups of oats.

Using the table you can write this proportion:

\frac{\frac{2}{3} }{2}=\frac{s}{3}

Solving for "s", you get:

\frac{1}{3}=\frac{s}{3}\\\\s=1

6 0
3 years ago
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