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3 years ago

What’s the answer I need it please

Mathematics

1 answer:

USPshnik [31]3 years ago

5 0

Answer: the answer is a

Step-by-step explanation:

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Identify the coefficient in each term

Archy [21]

Answer:

5. 4

6. 1

7. 2

8. -1

Step-by-step explanation:

Coefficient is usually the whole number in the beginning. I believe 5-7 are correct. I'm a little iffy about 8. Good luck!

8 0

3 years ago

Let X be a random variable with probability mass function P(X = 1) = 1 2 , P(X = 2) = 1 3 , P(X = 5) = 1 6 (a) Find a function g

Goryan [66]

The question is incomplete. The complete question is :

Let X be a random variable with probability mass function

P(X =1) =1/2, P(X=2)=1/3, P(X=5)=1/6

(a) Find a function g such that E[g(X)]=1/3 ln(2) + 1/6 ln(5). You answer should give at least the values g(k) for all possible values of k of X, but you can also specify g on a larger set if possible.

(b) Let t be some real number. Find a function g such that E[g(X)] =1/2 e^t + 2/3 e^(2t) + 5/6 e^(5t)

Solution :

Given :

$P(X=1)=\frac{1}{2}, P(X=2)=\frac{1}{3}, P(X=5)=\frac{1}{6}$

a). We know :

$E[g(x)] = \sum g(x)p(x)$

So, $g(1).P(X=1) + g(2).P(X=2)+g(5).P(X=5) = \frac{1}{3} \ln (2) + \frac{1}{6} \ln(5)$

$g(1).\frac{1}{2} + g(2).\frac{1}{3}+g(5).\frac{1}{6} = \frac{1}{3} \ln (2) + \frac{1}{6} \ln (5)$

Therefore comparing both the sides,

$g(2) = \ln (2), g(5) = \ln(5), g(1) = 0 = \ln(1)$

$g(X) = \ln(x)$

Also, $g(1) =\ln(1)=0, g(2)= \ln(2) = 0.6931, g(5) = \ln(5) = 1.6094$

b).

We known that $E[g(x)] = \sum g(x)p(x)$

∴ $g(1).P(X=1) +g(2).P(X=2)+g(5).P(X=5) = \frac{1}{2}e^t+ \frac{2}{3}e^{2t}+ \frac{5}{6}e^{5t}$

$g(1).\frac{1}{2} +g(2).\frac{1}{3}+g(5).\frac{1}{6 }= \frac{1}{2}e^t+ \frac{2}{3}e^{2t}+ \frac{5}{6}e^{5t}$$

Therefore on comparing, we get

$g(1)=e^t, g(2)=2e^{2t}, g(5)=5e^{5t}$

∴ $g(X) = xe^{tx}$

7 0

2 years ago

Solve (x-5)^2- 45 = 0, where x is a real number

sdas [7]

Answer:

Step-by-step explanation: the answer is x= 3 $\sqrt{5}$ +5, -3 $\sqrt{5}$ +5

5 0

3 years ago

Jason spent half of his allowance going to the movies. he washed the family car and earned 8 dollars. What is his weekly allowan

oksian1 [2.3K]

$6 dollars because 11-8 = 3, 3x2 =6

3 0

3 years ago

Read 2 more answers

Find the equation of the tangent at the point (1.1) for the function Y given in the equation

Likurg_2 [28]

If y = y(x), then the slope of the tangent line to (1, 1) is equal to the value of the derivative dy/dx when x = 1 and y = 1.

Compute the derivative using implicit differentiation:

d/dx [xy ^2 + y] = d/dx [2x]

d/dx [xy ^2] + d/dx [y] = 2 d/dx [x]

(x d/dx [y ^2] + d/dx [x] y ^2) + dy/dx = 2

2xy dy/dx + y ^2 + dy/dx = 2

(2xy + 1) dy/dx = 2 - y ^2

dy/dx = (2 - y ^2) / (2xy + 1)

Plug in x = 1 and y = 1 :

slope = dy/dx = (2 - 1^2) / (2*1*1 + 1) = 1/3

Now use the point-slope formula to get the equation of the line:

y - 1 = 1/3 (x - 1)

y = x/3 + 2/3

6 0

3 years ago