The genotype for the possible children is 'AATt, AAtt, Aatt, AaTt'. Woman has normal pigment which means she must have at-least one' 'A. her father is albino and albino allele is recessive , so his genotype is 'aa'. Then 'Aa' genotype is present in skin.
Woman cannot taste PTC because the ability ti taste PTC is dominant .So 'tt' genotype is present for tasting trait. Putting both the trait the woman's genotype is 'Aatt'.
(PTC) Phenylthiocarbamide tasting is a trait governed by pair of alleles , 'T' is for tasting dominant and recessive 't' is for non- tasting.The genotype of parents perform a punnett square to determine the F1 offspring. And the genotype of possible children can be determine.
To learn more about Phenylthiocarbamide tasting here
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Answer:
Option A, The lymphocytes express antigens specific for the antibodies in the assay
Explanation:
The options for the question are
a) The lymphocytes express antigens specific for the antibodies in the assay
b) The lymphocytes do not have antigens specific for the antibodies in the assay
c) This is not a valid method for identifying HLA agents.
Solution -
The aim of conducting this assay is to use the ability of the microlymphocytotoxicity assay (CdL) to detect the antibodies specific to the antigens based on the complement dependent assay.
The B and T lymphocytes are tested at both warm and cold temperatures and then the result obtained is compared with other non –complement based test results. HLA-ABC alloantibodies are weak in reactivity and specific to B cell hence they can be identified only through the CdL assay.
Hence, option A is correct
Inside of the woman's body the sperm can live up to 5-6 days. Depending on conditions it arrives on. it will in which survive for approximately 1 day(2)
Hope this helps
~Renee ^_^
