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2 years ago

How many numbers are between 1 and 100 that are divisible by 2 and 5?

Mathematics

1 answer:

alexdok [17]2 years ago

6 0

Answer:

Step-by-step explanation:

if 100 digits are in 80 then 2 and 5 are divisble in a 100 15 times

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What are the dimensions of the poster at 1/3 it’s current size?

Nimfa-mama [501]

Answer:

Step-by-step explanation:

divide 9 and 6 each by 3 and bam you got a 2x3 poster

7 0

2 years ago

The hawks soccer team won 12 out of 14 games. If this rate continues, how many games will they win if they play a total of 21 ga

Schach [20]

1) 12 out of 14 = 85% Win Rate
2) Now you have to figure out what is 85% of 21 so you have to plug in what you have ? out of 21 = .85
3) Multiply 21 x .85
4) Answer is They will win 18 out of 21 games

8 0

2 years ago

Select the missing numbers. Remember to indicate a negative cash flow with parentheses.

cluponka [151]

To find the cash flow, subtract the Cash Disbursements from the sales receipts for each month.

January: 110 - 135 = -$25

February: 85 - 110 = -$25

March: 100 - 95 = $5

April: 130 - 95 = $35

May: 145 - 100 = $45

June: 165 - 105 = $60

4 0

2 years ago

Someone please help me with this lol… have no idea what I’m doing

Sholpan [36]

Given:

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

To find:

The quadrant of the terminal side of $\theta$ and find the value of $\sin\theta$ .

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

Here cos is positive and sine is negative. So, $\theta$ must be lies in Quadrant IV.

We know that,

$\sin^2\theta +\cos^2\theta =1$

$\sin^2\theta=1-\cos^2\theta$

$\sin \theta=\pm \sqrt{1-\cos^2\theta}$

It is only negative because $\theta$ lies in Quadrant IV. So,

$\sin \theta=-\sqrt{1-\cos^2\theta}$

After substituting $\cos \theta =\dfrac{3}{5}$ , we get

$\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}$

$\sin \theta=-\sqrt{1-\dfrac{9}{25}}$

$\sin \theta=-\sqrt{\dfrac{25-9}{25}}$

$\sin \theta=-\sqrt{\dfrac{16}{25}}$

$\sin \theta=-\dfrac{4}{5}$

Therefore, the correct option is B.

6 0

2 years ago

Hellllllllllllllllllllllllllp

murzikaleks [220]

Answer:

$\begin{cases}y=-5x+1\\y=5x-4 \end{cases}$

Step-by-step explanation:

Slope-intercept form of a linear equation:

$\boxed{y=mx+b}$

where:

m is the slope.
b is the y-intercept (where the line crosses the y-axis).

Slope formula

$\boxed{\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}}$

Equation 1

Define two points on the line:

$\textsf{Let }(x_1,y_1)=(-1, 6)$

$\textsf{Let }(x_2,y_2)=(0, 1)$

Substitute the defined points into the slope formula:

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-6}{0-(-1)}=-5$

From inspection of the graph, the line crosses the y-axis at y = 1 and so the y-intercept is 1.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

$y=-5x+1$

Equation 2

Define two points on the line:

$\textsf{Let }(x_1,y_1)=(1, 1)$

$\textsf{Let }(x_2,y_2)=(0, -4)$

Substitute the defined points into the slope formula:

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-1}{0-1}=5$

From inspection of the graph, the line crosses the y-axis at y = -4 and so the y-intercept is -4.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

$y=5x-4$

Conclusion

Therefore, the system of linear equations shown by the graph is:

$\begin{cases}y=-5x+1\\y=5x-4 \end{cases}$

Learn more about systems of linear equations here:

brainly.com/question/28164947

brainly.com/question/28093918

5 0

1 year ago

Read 2 more answers