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maw [93]
3 years ago
13

Rewrite the function by completing the square. f(x)= x^{2} + x -30f(x)=x 2 +x−30f, left parenthesis, x, right parenthesis, equal

s, x, squared, plus, x, minus, 30 f(x)=f(x)=f, left parenthesis, x, right parenthesis, equals (x+(x+left parenthesis, x, plus )^2+) 2 +right parenthesis, squared, plus
Mathematics
1 answer:
Verizon [17]3 years ago
6 0

Answer:

f(x)= (x+\frac{1}{2} )^{2}-30\frac{1}{4}

Step-by-step explanation:

f(x)= x^{2} + x -30

To re-write the function by completing the square, the procedure is to first

(i)take the coefficient of x

(ii)Divide it by 2 and Square it

Coefficient of x=1

Divided by 2 = 1/2

Square of 1/2 = (\frac{1}{2} )^{2}

Next, we add it to the function and subtract same so that the equation remains balanced

f(x)= x^{2} + x +(\frac{1}{2} )^{2}-(\frac{1}{2} )^{2}-30

Pick each of the squared term and square the sum

f(x)= (x+\frac{1}{2} )^{2}-(\frac{1}{2} )^{2}-30

f(x)= (x+\frac{1}{2} )^{2}-30\frac{1}{4}

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Answer:

x=\frac{2}{3}, -4

Step-by-step explanation:

hope this helps!

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3 years ago
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

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4 0
4 years ago
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3 years ago
A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\

\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
4 years ago
789,091 to the nearest ten thousand
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i think it's 790,000 or 800,000 i hope i helped

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