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3 years ago

14

you have 1000 to invest in an account and you need to have 1500 in one year what interest rate would you need to have in order t

o reach this goal if the amount is compounded quarterly round your answer to the nearest percent. Can someone help me please

1 answer:

Anna007 [38]3 years ago

3 0

Answer: 42.7%

Step-by-step explanation:

A = p (1+r/n)^nt

1500 = 1000 (1 + r/4)^4x1

r = 42.673

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Which transfromations tranforms the graph of f(x)=x^2 to the graph of g(x)=(x+4)^2?

wariber [46]

<em>Greetings from Brasil...</em>

In function F(X) = X², if we replace X with X + 4 we will have exactly function G(X) = (X + 4)²

So, just replace X for X + 4..... This will be responsible for translating 4 units to the left, because:

F(X) = X²

F(X + 4) = (X + 4)²

F(X + 4) ⇔ F(X + k) <em> see below</em>

We know that the translations are established as follows:

→ Horizontal

F(X + k) ⇒ k units to the left

F(X - k) ⇒ k units to the right

<em>see more:</em>

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3 years ago

I WILL MARK BRAINLIEST A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to buil

Alona [7]

Using a system of equations, it is found that since 20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

Variable c: number of child bikes.

Variable a: number of adult bikes.

Each child bike requires 4 hours to build, as do each adult bike. The company has 100 hours of testing, hence:

4c + 4a = 100.

c + a = 25.

With 20 child bikes and 6 adult bikes in a week, we have that c = 20, a = 26, hence:

c + a = 26

20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

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2 years ago

8 8/9 - 5 1/11???????????????????????

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Answer:

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$4 \frac{25}{99}$

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3 years ago

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A football is kicked into the air. The height of the football can be modeled by the equation

Alinara [238K]

Answer:

x = 0 and x = 1

Step-by-step explanation:

Given that,

A football is kicked into the air. The height of the football can be modeled by the equation :

$h = -16x^2 + 16x$

Where

h is the height reached by the ball after x seconds

When it touches the ground, h = 0

So,

$-16x^2 + 16x=0\\\\16x(-x+1)=0\\\\x=0\ and\ x=1$

So, it will touch the ground at x = 0 and x = 1 seconds.

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3 years ago

The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in

Stolb23 [73]

Answer:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=34.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=300-1=299$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that $t_{\alpha/2}=1.653$

And the margin of error is given by:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

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3 years ago

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