Since ΔABC ~ ΔEDC, ∠B = ∠D.
Since both triangles appear to be similar, the corresponding angles are the same, and corresponding sides are the same or have the same ratio.
We can write an equation to resemble the problem:
8x + 16 = 120
Solve for x.
8x + 16 = 120
~Subtract 16 to both sides
8x + 16 - 16 = 120 - 16
~Simplify
8x = 104
~Divide 8 to both sides
8x/8 = 104/8
~Simplify
x = 13
Therefore, the answer is 13.
Best of Luck!
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
-35-5
Step-by-step explanation:
-35-5=-40
which is negative
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