Question

what is the point slope form of the equation for the line with a slope of -8 that passes through the point (5, -3) ?

Answer 1

ANSWER

The point slope form is $y+3=-8(x-5)$

EXPLANATION

The point slope form of the equation of a straight line is given by the formula;

$y-y_1=m(x-x_1)$.

Where $m$ is the slope of the straight line and the point $(x_1,y_1)$ lies on the line.

We were given the slope to be $-8$. This means that $m=-8$.

We were also given that the point $(5,-3)$ lies on the line.

We substitute all these values in to the above equation to obtain,

$y--3=-8(x-5)$

This simplifies to

$y+3=-8(x-5)$

The correct answer is D

Answer 2

We know that the form of line passing through point (x₀ , y₀) and having slope m is :

$\clubsuit$  y - y₀ = m(x - x₀)

Here the line passes through the point (5 , -3)

⇒ x₀ = -2 and y₀ = -5

Given : Slope(m) = -8

Substituting all the values in the standard form, We get :

Equation of the line : y + 3 = -8(x - 5)