All categories

3 years ago

Which is the correct calculation for the volume of the pyramid?

Mathematics

2 answers:

Leya [2.2K]3 years ago

7 0

Answer:

h×a²×1/3

Step-by-step explanation:

where h is the vertical height of pyramid a is the length of base ..this formula is applicable for square based pyramid only.

Svetach [21]3 years ago

5 0

Answer:

1/3 A h.

Step-by-step explanation:

The volume of a pyramid is 1/3 * area of the base * height = 1/3 A h.

So for example the area of a square-based pyramid = 1/3 s^2 h where s is the length of a side of the square.

You might be interested in

Add the following two numbers in scientific notation.

strojnjashka [21]

Answer:

3.31 x 10^4

Step-by-step explanation:

3.111 x 10^4 is 31110

2 x 10^3 is 2000

31110 + 2000 = 33100 or 3.31 x 10^4

4 0

1 year ago

Read 2 more answers

The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?

Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

$N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}$

where,

$N(t)$ = quantity of the substance remaining

$N_0$ = initial quantity of the substance

$t$ = time elapsed

$t_{1/2}$ = half life of the substance

From the information given we know:

The initial quantity of silicone-32 is 30 g.
The time elapsed is 300 years.
The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

$N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g$

22.38 g of silicone-32 will be present in 300 years.

7 0

3 years ago

Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each ho

marissa [1.9K]

1st Avenue would be more difficult because it’s rise and run is for every one foot forward it is 3 feet up. Meanwhile avenue 16th would start at (3,1) and the rise and run would be for every 3 feet it would go up 1 foot.

7 0

3 years ago

Read 2 more answers

Solve the system of linear equations using<br> substitution. Y=x-3 <br> Y=8x-31

Georgia [21]

Answer:

x=4 y=1 or (4,1)

Step-by-step explanation:

3 0

3 years ago

Suzanne has a rectangular garden which is 18 feet long and 11 feet wide. She has 168 square foot of paving stones, and she wants

VikaD [51]

Answer:

width = 2.5 feet

Step-by-step explanation:

Suzanne has a rectangular garden which is 18 feet long and 11 feet wide.

Area of the garden = length times width = 18 times 11= 198 square foot

Let 'w' be the width of the border

Length of the garden with border = 18+2w

Width of the garden with border = 11+2w

Area of the garden with border = $(18+2w)(11+2w)=4w^2+58w+198$

Area of the border = $4w^2+58w+198-198=4w^2+58w$

She has 168 square foot of paving stones,

$4w^2+58w=168$

Solve for w

apply quadratic formula

a= 4, b= 58 and c=-168

$\quad x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$w=\frac{-58+-\sqrt{58^2-4\cdot \:4\left(-168\right)}}{2\cdot \:4}$

$w=\frac{-58+-\sqrt{6052}}{8}$

we get two values for w

$w=\frac{-58+\sqrt{6052}}{8}=2.47$

$w=\frac{-58-\sqrt{6052}}{8}=-16.97$

5 0

3 years ago