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xeze [42]
3 years ago
13

When I use a coordinate plane and i'm on the bottom left ...which number would i put first the one on the x axis or the one on t

he y axis like (-A,-B) ?
Mathematics
2 answers:
VikaD [51]3 years ago
8 0

Answer:

the one on X axis, kinda like the alphabet, x comes before y so you put the number resembling X first, then put the number resembling Y

Serga [27]3 years ago
3 0

Answer:

(-x, -y)

Step-by-step explanation:

The bottom left of the coordinate plane, or quartile 3, is to the left of the x axis origin and below the y axis origin. The x axis and the y axis are merely number lines. To the left of zero are the negatives, and to the right are positives. X is always first, so it would be (-x, -y).

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bogdanovich [222]

Answer:

D 57

Step-by-step explanation:

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3 years ago
Which equation matches the function shown in the graph?
borishaifa [10]

Answer:

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5 0
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Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and
Anastaziya [24]
The problem is modelled in the first picture shown below

To work out the resultant vector, we modelled the vectors 150N and 75N as triangle AOB is shown in the second picture with AB as the resultant vector. 

We use the cosine rule to work out the length AB
AB^{2}= 75^{2}+ 150^{2}-(2*75*150*cos(60))
AB^{2} =28125-11250
AB^{2}=16875
AB= \sqrt{16875} =130(nearest whole number)

The third picture shows the full diagram of the vectors

To work out the direction of the resultant vector, we use the sin rule to find the size of angle A and angle B

Angle A
\frac{130}{sin(60)}= \frac{75}{sin(A)}
130sin(A)=75sin(60)
sin(A)= \frac{75sin(60)}{130}
sin(A)=0.4996300406
A= sin^{-1}(0.4996300406)
A=30 (rounded to nearest whole number)

Angle B
B=180-60-30=90

Direction is 60° toward negative x-axis

Answer: Magnitude 130N and direction 60° toward negative x-axis

3 0
3 years ago
Convert -√3-i to polar form.
Jlenok [28]

Answer:

-sqrt(3) -i = 2 cis (7pi/6)

Step-by-step explanation:

-sqrt(3) -i

We can find the radius

r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)

  = sqrt( 3 + 1)

  = sqrt(4)

  = 2

theta = arctan (y/x)

          arctan (-1/-sqrt(3))

         arctan (1/sqrt(3))

theta = pi/6

But this is in the first quadrant, and we need it in the third quadrant

Add pi to move it to the third quadrant

theta = pi/6 + 6pi/6

         =7pi/6


-sqrt(3) -i = 2 cis (7pi/6)

6 0
3 years ago
Read 2 more answers
The sum of two integers is two times their difference. Which of the following algebraic equations demonstrates this? A) (x + y)
netineya [11]

Answer:

It is A)

Step-by-step explanation:

3 0
3 years ago
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