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Margarita [4]
3 years ago
6

Plz help me you guys I will give you a point

Mathematics
1 answer:
iragen [17]3 years ago
8 0
The big bang is a theory of how our universe began. Dust that created the stars and planets came from the epicenter of the big bang and it's the same dust that makes up you and every other living or non-living thing in existence. This relies on the big bang being true. 
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3.) The height of the baseball can be modeled by the function Hs= -16s2+96s where s represents the time in seconds the ball is i
Aleks04 [339]

Answer:

what's the topic hahhahahahah

3 0
3 years ago
What is the y intercept of . y = ½x -5
seraphim [82]

Answer: (0, 10) or 10

Step-by-step explanation:

plug 0 into y

(0) = 1/2x - 5

1/2x - 5 = 0

      + 5 + 5

1/2x = 5

* 2    * 2

x = 10

8 0
3 years ago
Calcule a área da região sombreada da figura abaixo.<br> 120°<br> 4 cm<br> B
masya89 [10]

Answer:

Area of segment = 9.8 cm² (Approx.)

Step-by-step explanation:

Given:

Angle θ = 120°

Radius of circle = 4 cm

Find:

Area of segment

Computation:

Area of segment = [θ/360][π][r]² - [1/2][r²][sinθ]

Area of segment = [120/360][3.14][4]² - [1/2][4²][sin120]

Area of segment = [0.333][3.14][16] - [0.5][16][0.866]

Area of segment = 16.7299 - 6.28

Area of segment = 9.8019

Area of segment = 9.8 cm² (Approx.)

8 0
3 years ago
A 1,200g block of phosphorus-32, which has a half life of 14.3 days, is stored for 100.1 days. At the end of this period, how mu
Valentin [98]

Answer:

The amount of phosphorus-32 left after 100.1 days is <u>9.3 g</u>.

Step-by-step explanation:

Given:

Initial amount of Phosphorus-32 is, N_0=1200\ g

Time period of decay is, t=100.1\ days

Half life of the block is, t_{1/2}=14.3\ days

Now, final amount left is, N=?

We know that, the decay equation for a radioactive material is given as:

N=N_0e^{-kt}\\k\to decay\ constant

The value of the decay constant is given as:

k=\frac{\ln 2}{t_{1/2}}\\\\k=\frac{0.693}{14.3}=0.0485

Now, plug in all the given values and calculate 'N'. This gives,

N=(1200)e^{(-0.0485\times 100.1)}\\\\N=9.349\approx 9.3\ g

Therefore, the amount of phosphorus-32 left after 100.1 days is 9.3 g

5 0
3 years ago
The graph shows the volume of oil (L litres) in a tank at time t seconds. a)find the gradient of the graph b)explain what this g
Alisiya [41]

Answer/Step-by-step explanation:

a. Using two points on the line (0, 2) and (4, 12), find the gradient:

Gradient = ∆y/∆x = (12 - 2) / (4 - 0) = 10/4 = 2.5

Gradient = 2.5

b. The gradient, 2.5, represents the unit rate. That is, the volume of the oil in the tank per second.

i.e. 2.5 litres per second

c. The value, L = 2 represents the y-intercept, which is the starting value or initial volume of oil in the tank at 0 secs.

4 0
3 years ago
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