Answer:
Figure G.
Step-by-step explanation:
Let's check through the values and calculate the radius and area for all the circle.
For circle R
Diameter = 2 feet
Radius= 1 feet
Area= πr²
Area= 3.14*1
Area= 3.14 feet²
CircleS
Diameter= 4 feet
Radius= 2 feet
Area= πr²
Area= 3.14*2²
Area= 12.56 feet²
Circle T
Diameter= 8 feet
Radius= 4 feet
Area = π r²
area= 3.14*4²
Area=50.24 feet²
Circle U
Diameter= 12 feet
Radius= 6 feet
Area = π r²
area= 3.14*6²
Area=113.04 feet²
The values of the radius and Area all match the graph in figure G
Answer:
(a) 9 buildings
(b) 2^n -1
Step-by-step explanation:
The number of distinct non-empty subsets of b objects is 2^b -1. Since the subsets are distinct, each could represent a list of the buildings, from the set of b buildings, in which a student is taking courses.
(a) For 8 buildings, 2^8 -1 = 255 students could enroll. for 9 buildings, 2^9-1 = 511 students could enroll.
For 500 students, 9 buildings are required.
__
(b) The maximum number of students for n buildings is ...
2^n -1
Answer:
$132
Step-by-step explanation:
First we need to find the total number of woods required. This would be total area of fence divided by area of each wood. Remember to convert inch into feet.
Now we know the total number of planks, we need to find what is the cost of each plank. We know that one wood plank area is 2 sq. ft ( 6*0.33333). Therefore, the cost of each plank is = cost per area(sq.ft) multiply by total area (sq. ft).
cost per plank = 2 * $1.10 =$2.20.
We have total planks = 60 units and we have cost per plank = $2.20.
So, we can find total cost as 60*2.20= $132
Answer: Derrick wants an air conditioner in his living room. It is a rectangular room that measures 13 feet by 15 feet. The room is well insulated and is on the east side of the house. It has an 8-foot-high ceiling. How large of an air conditioner would this room require? Round to the nearest thousand BTUs, hope this helped :)
Step-by-step explanation:
