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Umnica [9.8K]
3 years ago
10

Santa's elves are selling

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0

cost of one peppermint cookies = $ 0.6

cost of one cinnamon sugar cookies = $ 0.3

<h3><u>Solution:</u></h3>

Let "p" be the cost of one peppermint cookies

Let "c" be the cost of one cinnamon sugar cookies

<u><em>To find: cost of each cookie</em></u>

<h3><u><em>On  the first day, they sold 120  peppermint cookies and 30  cinnamon sugar cookies for a  total of $81</em></u></h3>

We can frame a equation as:

120  peppermint cookies x cost of one peppermint cookies + 30  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 81

120 \times p + 30 \times c = 81

120p + 30c = 81  --------- eqn 1

<h3><u><em>The next day  they made $60 by selling 70  peppermint cookies and 60  cinnamon sugar cookies</em></u></h3>

70  peppermint cookies x cost of one peppermint cookies + 60  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 60

70 \times p + 60 \times c = 60

70p + 60c = 60 --------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "p" and "c"

Multiply eqn 1 by 2

240p + 60c = 162  --- eqn 3

Subtract eqn 2 from eqn 3

240p + 60c = 162

70p + 60c = 60

(-) -------------------------

170p = 102

<h3>p = 0.6</h3>

Substitute p = 0.6 in eqn 1

120p + 30c = 81

120(0.6) + 30c = 81

72 + 30c = 81

30c = 9

<h3>c = 0.3</h3>

<u><em>Summarizing the results:</em></u>

<em>cost of one peppermint cookies = $ 0.6</em>

<em>cost of one cinnamon sugar cookies = $ 0.3</em>

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