Answer:
Build a global action to create Contacts
Explanation:
Based on the information given the mobile solution that an app builder should recommend should be GLOBAL ACTION because global action enables new contact to be created quickly ,Global actions also enables the creation or update of records as well sending email, all without leaving the page the person is working on which is why GLOBAL ACTION is often recommended because it saves time.
Answer:
Step 1: Questioning --- Before going on the Internet, students should structure their questions. Step 2: Planning --- Students should develop a search strategy with a list of sites to investigate. Step 3: Gathering --- Students use the Web to collect and gather information.
Explanation:
there i did it for you can I get brainlyest
Answer:
B. Application programming interface
Explanation:
An application programming interface (API) is an interface or communication protocol between different parts of a computer program intended to simplify the implementation and maintenance of software. An API may be for a web-based system, operating system, database system, computer hardware, or software library.
Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).
Answer:
Here’s one!
Given [math]R[/math], the radius of the circle.
Let [math]N,D\leftarrow 0[/math]
Repeat until [math]D[/math] is large enough (about 1,000,000)
[math]x,y\leftarrow U[0,1][/math]
If [math]x^2 + y^2\le 1[/math] then [math]N\leftarrow N+1[/math]
[math]D\leftarrow D+1[/math]
[math]P\leftarrow\frac{8NR}{D}[/math]
Return [math]P[/math]
[math]U[0,1][/math] is a uniform random number in the range [math][0,1][/math].
Explanation:
