Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
Answer:
75, 77
Step-by-step explanation:
Let the first odd number = 2x -1
Let the second odd number = 2x + 1
2x - 1 + 2x + 1 + 18 = 170 Combine like terms on the left.
4x + 18 = 170 Subtract 18 from both sides.
4x = 170 - 18 Combine like terms on the right
4x = 152 Divide by 4
4x/4 = 152/4
x = 38
2 * 38 - 1 = 75
2 * 38 + 1 = 77
sorry i dont have answered
Answer:
-22
Step-by-step explanation:
Put -4 where x is and do the arithmetic.
f(-4) = 3(-4) -10 = -12 -10
f(-4) = -22
Answer:
We can solve this question using the slope equation which is y2-y1/x2-x1
If you use that formula and sub in the coordinates
-4 - 5 / -1-2
-9/-3
= 3
The slope should be 3/1