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devlian [24]
4 years ago
13

Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake

in the graph?
AJ graphs the function f(x) = -(x + 2)^2 - 1 as shown below.

Mathematics
1 answer:
Mnenie [13.5K]4 years ago
5 0

Answer:

See explanation

Step-by-step explanation:

The function AJ graphed is f(x)=-(x+2)^2-1.

When x=0, we get f(0)=-(0+2)^2-1

This implies f(0)=-4-1=-5

When x=1f(1)=-(1+2)^2-1=-3^2-1=-9-1=-10

All the values we evaluated between -5 and 5 gives negative value.

This means that AJ's graph should have turn upside down

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Answer:

y = -2x -2

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2x + y = -2 } we eliminate 2x

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