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irina1246 [14]
3 years ago
13

Can you please help me answer this problem

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

They are not similar

Step-by-step explanation:

Similar triangles are of same size

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Can someone tell me the answer and show me how to find it?
kiruha [24]

Answer:

The value of x is 20°

Step-by-step explanation:

Given that angle in a straight line is 180°. Then you can find the value of x:

55° + (6x+5)° = 180°

55° + 6x + 5° = 180

6x + 60° = 180°

6x = 180 - 60

6x = 120°

x = 20°

6 0
2 years ago
What is the equation of a line perpendicular to y= 3x +6 that crosses the ordered pair (3,2).
jasenka [17]

Answer:

y=-\frac{1}{3}x+3

Step-by-step explanation:

5 0
2 years ago
4-1/x divided by 16-1/xsquared
Vladimir [108]
4 - 1/x (16)-1/x 2  
4x-18/x
3 0
3 years ago
Determine if Ginny factored correctly. If not, explain where she made an error. Ginny made a mistake in step 1 when she identifi
il63 [147K]

Quadratic equations are second-order equations. Ginney made a mistake when she identified b = 31. It should be b = –31.

<h3>What is a Quadratic Equation?</h3>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

In order to find the mistake that Ginny made, we will first find the factors ourselves, therefore, we will factorize the trinomial,

6x^2 - 31x -30 = 0

As we can see that the value of constants are,

a = 6

b = -31

c = 30

6x^2 - 31x -30 = 0\\\\6x^2 - 36x+5x -30 = 0\\\\6x(x-6)+5(x-6)=0\\\\(6x+5)(x-6)=0

Therefore, the factors of the trinomial 6x^2 - 31x -30 = 0 are (6x+5) and (x-6).

If we compare our process with Ginny's process, we will find that she has taken the value of the constant b as 31 which is wrong.

Hence, Ginney made a mistake when she identified b = 31. It should be b = –31.

Learn more about Quadratic Equation:

brainly.com/question/17177510

3 0
2 years ago
Read 2 more answers
Help ppppppppppppllllllllllllllllsssssssss
marissa [1.9K]

Answer:

option b)

tan²θ + 1 = sec²θ

Step-by-step explanation:

The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.

hypotenuse² = height² + base²

Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.

<h3>1)</h3>

sin²θ + 1 = cos²θ     incorrect

<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>

by dividing first identity by cos²θ

sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ

<h3>tan²θ + 1 = sec²θ  correct</h3><h3 /><h3>3)</h3>

1 - cot²θ = cosec²θ  incorrect

by dividing first identity by sin²θ

sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ

<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>

1 - cos²θ  = tan²θ

not such pythagorus identity exists

4 0
3 years ago
Read 2 more answers
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