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SIZIF [17.4K]
3 years ago
15

Can this expression be simplified anymore?

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0
I believe not, but that does look about right.
Afina-wow [57]3 years ago
4 0

Answer:

I believe is a true to become a good expression

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Solve −2x2 +3x − 9 = 0
luda_lava [24]
-2x^2 + 3x - 9 = 0
The quadratic is not factorable so quadratic formula must be used.
x = (-b + - √(b^2 - 4ac))/2a
a = -2, b = 3, c = -9
x = (-3 + - √(9 - 4*-2*-9))/-4
x = (-3 + - √(-63))/-4
x = -3 + - 3i√7
     --------------
           -4
x = 3 + 3i√7            x = 3 - 3i√7
    ------------                ------------
         4                              4
8 0
3 years ago
What is the value of x?
Nonamiya [84]

Answer:

9x-3x(2-4)=6x(3x+4)-6(3x-2)

3 0
3 years ago
Sheila buys two concert tickets from her friend.
irina [24]

Answer:

15 because the 2 tickets were originally 105

Step-by-step explanation:

52.50 x 2 = 105 because 52 + 52 = 104 and .50 + .50 = 1 so 104 + 1 = 105

7 0
3 years ago
Verify that (a+b)+c = a+ (b+c) by taking a = -8 , b = (-8/11) , c = (-8/12)
gogolik [260]

Answer:

Step-by-step explanation:

(-8+-\frac{8}{11} ) + (-\frac{8}{12}) = -\frac{96}{11} + (-\frac{2}{3}) = -\frac{288 + 22}{33}) = -\frac{310}{33}\\ (-8) + (-\frac{8}{11} + (-\frac{2}{3})) = (-8) + (-\frac{46}{33})= -\frac{310}{33}

6 0
4 years ago
Read 2 more answers
Find the times (to the nearest hundredth of a second) that the weight is halfway to its maximum negative position over the inter
hoa [83]

Answer:

0.20 and 0.36

Step-by-step explanation:

y(t) = 2 sin (4π t) + 5 cos (4π t)

We wish to convert this to:

y = A sin(ωt + φ)

We know that ω = 4π.  We also know the following:

5 = A sin φ

2 = A cos φ

Divide the first equation by the second equation:

5/2 = tan φ

φ = tan⁻¹(5/2)

Now, square the two equations and add them together.

5² + 2² = (A sin φ)² + (A cos φ)²

29 = A²

A = √29

The equation of the wave is therefore:

y = √29 sin(4π t + tan⁻¹(5/2))

The maximum negative position is -√29.  And half of that is -½√29.

-½√29 = √29 sin(4π t + tan⁻¹(5/2))

-½ = sin(4π t + tan⁻¹(5/2))

7π/6 + 2kπ or 11π/6 + 2kπ = 4π t + tan⁻¹(5/2)

7 + 12k or 11 + 12k = 24t + 6 tan⁻¹(5/2) / π

t = (7 + 12k − 6 tan⁻¹(5/2) / π) / 24 or (11 + 12k − 6 tan⁻¹(5/2) / π) / 24

Trying different integer values of k, we find there are two possible values for t between 0 and 0.5, both when k = 0.

t = (7 − 6 tan⁻¹(5/2) / π) / 24 or (11 − 6 tan⁻¹(5/2) / π) / 24

t ≈ 0.20 or 0.36

5 0
3 years ago
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