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3 years ago

Rewrite each algebraic expression with fewer terms

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

6 0

1) solving $9.5(a + 4)-a$ we get $8.5a+38$

2) Solving $8 + h- 2\times 5$ we get $-2+h$

Step-by-step explanation:

Rewrite each algebraic expression with fewer terms

$1) 9.5(a + 4)-a$

Solving:

Multiplying 9.5 with terms inside the bracket

$9.5(a + 4)-a\\=9.5a+38-a\\=8.5a+38$

So, solving $9.5(a + 4)-a$ we get $8.5a+38$

$8 + h- 2\times 5$

Solving:

$8 + h- 2\times 5\\=8+h-10\\Combining\,\,like\,\,terms:\\=8-10+h\\=-2+h$

So, Solving $8 + h- 2\times 5$ we get $-2+h$

Keywords: Solving algebraic expression

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How heavy a load (pounds) is needed to pull apart pieces of wood 4 inches long and 1.5 inches square? Here are data from student

statuscvo [17]

Answer:

a. (29526.192 , 32155.808)

b. (29673.9301 , 32008.0699)

Step-by-step explanation:

on calculation, we find that sample mean = 30843 and sample standard deviation = 3018.504, and n=20

Sample Mean = 30841

SD = 3000

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 670.8204

alpha (a) = 1 - 0.95 = 0.05

z critical value for 95% confidence interval:

z(a/2) = z(0.025) = 1.96

Margin of Error (ME) = z(a/2) x SE = 1314.808

95% confidence interval is given by:

Sample Mean +/- (Margin of Error) = 30841 +/- 1314.808

= (29526.192 , 32155.808)

2)when std dev of population is not known, we use sample's, but we have to use t instead of z

Sample Mean = 30841

SD = 3018.504

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 674.958

alpha (a) = 1-0.9 = 0.1

we use t-distribution as population standard deviation is unknown

t(a/2, n-1 ) = 1.7291

Margin of Error (ME) = t(a/2,n-1)x SE = 1167.0699

90% confidence interval is given by:

Sample Mean +/- (Margin of Error)

30841 +/- 1167.0699 = (29673.9301 , 32008.0699)

4 0

3 years ago

From a pack of 9 cards numbered 1-9, three cards are drawn at random and laid on a table from left to right.

Andreas93 [3]

Answer: 1/6
Explanation: Since we need to draw three cards from a pack of 9 and the digits require an order, then our sample space becomes: 9P3.
Now, we don't care about picking an order when picking three cards to analyse, as there is only 1 way in arranging the three cards in descending order.

Thus, we get:

$\frac{^{9}C_3}{^{9}P_3} = \frac{1}{6}$