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3 years ago

Rewrite each algebraic expression with fewer terms

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

6 0

1) solving $9.5(a + 4)-a$ we get $8.5a+38$

2) Solving $8 + h- 2\times 5$ we get $-2+h$

Step-by-step explanation:

Rewrite each algebraic expression with fewer terms

$1) 9.5(a + 4)-a$

Solving:

Multiplying 9.5 with terms inside the bracket

$9.5(a + 4)-a\\=9.5a+38-a\\=8.5a+38$

So, solving $9.5(a + 4)-a$ we get $8.5a+38$

$8 + h- 2\times 5$

Solving:

$8 + h- 2\times 5\\=8+h-10\\Combining\,\,like\,\,terms:\\=8-10+h\\=-2+h$

So, Solving $8 + h- 2\times 5$ we get $-2+h$

Keywords: Solving algebraic expression

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Does Anybody know this? Find the area of the shaded sector

Sunny_sXe [5.5K]

Step-by-step explanation:

your teacher was very nice and warned you about the trap in the question.

so, really, what do we have to do ?

a full circle represents 360°.

the shaded sector is the full circle minus the white sector !

this is the same as directly calculating the shaded sector for 360-75 = 285°.

so, the area of a circle is

pi×r²

in our case

pi×20² = 400pi

the needed fraction of the whole circle is either

75/360, if we want to subtract it for the solution

285/360, if we want to calculate the solution directly.

both lead to the same result.

400pi×360/360 - 400pi×75/360 =

= 400pi × 285/360 = 10pi × 285/9 = 2850pi/9 =

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2 years ago

The half life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am

Veronika [31]

Using an exponential function, it is found that:

a) $N(t) = 75(0.5)^{\frac{t}{3.8}}$

b) 37.5 grams of the gas remains after 3.8 days.

c) The amount remaining will be of 10 grams after approximately 11 days.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

$A(t) = A(0)(1 - r)^t$

In which:

A(0) is the initial value.

r is the decay rate, as a decimal.

Item a:

We start with 75 grams, and then work with a half-life of 3.8 days, hence the amount after t daus is given by:

$N(t) = 75(0.5)^{\frac{t}{3.8}}$

Item b:

This is N when t = 3.8, hence:

$N(t) = 75(0.5)^{\frac{3.8}{3.8}} = 37.5$

37.5 grams of the gas remains after 3.8 days.

Item c:

This is t for which N(t) = 10, hence:

$N(t) = 75(0.5)^{\frac{t}{3.8}}$

$10 = 75(0.5)^{\frac{t}{3.8}}$

$(0.5)^{\frac{t}{3.8}} = \frac{10}{75}$

$\log{(0.5)^{\frac{t}{3.8}}} = \log{\frac{10}{75}}$

$\frac{t}{3.8}\log{0.5} = \log{\frac{10}{75}}$

$t = 3.8\frac{\log{\frac{10}{75}}}{\log{0.5}}$

$t \approx 11$

The amount remaining will be of 10 grams after approximately 11 days.

More can be learned about exponential functions at brainly.com/question/25537936

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1 year ago

A gardener wants to fence a circular garden of radius 21 m. Find the length of the rope.

Readme [11.4K]

Answer:

The length of the rope is 132m

Step-by-step explanation:

Given

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Required

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2 years ago

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2 years ago

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Dovator [93]

Answer:

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Step-by-step explanation:

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