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ddd [48]
3 years ago
12

How do you factor 6x - 42?

Mathematics
2 answers:
erik [133]3 years ago
7 0
Divide both side by 6
Than the answer is 7
That is your answer!
qwelly [4]3 years ago
6 0
Take out your greatest common factor, which would be 6 so your factored form would look like

6(x-7)
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How do I solve this?
ruslelena [56]
Sweetie listen know first step is to go to google use the calcalater then u will receive the answer u looking for plzzzzzzzzz come back to me if u didn't find it yah know.
3 0
3 years ago
The Students' Conjectures Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Po
noname [10]

Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

Answer:

A = B

Step-by-step explanation:

<em>See comment for complete question</em>

Given

A: (4x^2 - 4x)(x^2 - 4)

B: (x^2 + x - 2)(4x^2 - 8x)

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

A: (4x^2 - 4x)(x^2 - 4)

Factor out 4x

A: 4x(x - 1)(x^2 - 4)

Apply difference of two squares on x^2 - 4

A: 4x(x - 1)(x - 2)(x+2)

For, Polynomial B: We have:

B: (x^2 + x - 2)(4x^2 - 8x)

Expand x^2 + x - 2

B:(x^2 + 2x - x - 2)(4x^2- 8x)

Factorize:

B:(x(x + 2) -1(x + 2))(4x^2- 8x)

Factor out x + 2

B:(x -1) (x + 2)(4x^2- 8x)

Factor out 4x

B:(x -1) (x + 2)4x(x- 2)

Rearrange

B: 4x(x - 1)(x - 2)(x+2)

The simplified expressions are:

A: 4x(x - 1)(x - 2)(x+2) and  

B: 4x(x - 1)(x - 2)(x+2)

Hence, both polynomials are equal

A = B

3 0
3 years ago
Simplify 2x + 1 - x +2.​
Pavlova-9 [17]

Answer:

the answer is x + 3

Step-by-step explanation:

7 0
3 years ago
What is the length of the focal width x=-1/8y^2
Levart [38]
The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.

<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0</span><span>

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.</span>
3 0
3 years ago
Read 2 more answers
Store A
olga2289 [7]

Answer:

72

Step-by-step explanation:

3 0
3 years ago
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