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3 years ago

What is 5 - j = 3 ????

Mathematics

2 answers:

Mkey [24]3 years ago

7 0

Answer:

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1st step: again, reverse the equation (by flipping the equation around)

2nd step: do the equation ; 5 - 3 = 2

3rd step: (check your answer) ; 3 plus 2 equals 5

therefore, the answer 2 is correct.

VikaD [51]3 years ago

4 0

Answer:

j=2

Step-by-step explanation:

First, subtract by 5 from both sides of equation.

5-j-5=3-5

Simplify.

3-5=-2

-j=-2

Divide by -1 from both sides of equation.

-j/-1=-2/-1

Simplify, to find the answer.

-2/-1=2

It change negative to positive.

j=2 is the correct answer.

I hope this helps you, and have a wonderful day!

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Write the equation that describes the line with slope = 1 and y-intercept= 5/2 in slope-intercept form.

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Answer: y=x+5/2

Step-by-step explanation:

using the slope intercept formula, y=mx+b where m is the slope and b is the y-intercept, you can substitute the two values to get y=x+5/2. Please note that the slope, m, is one so it's not shown.

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3 years ago

Find f(3) for f(x) = 1/2(4)^x A. 8 B. 32 C. 6 D. 64

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3 years ago

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3 years ago

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Is 80 a multiple of 10? Explain why or why not

dimulka [17.4K]

Answer:

yes 80 is a mulitple of 10

Step-by-step

multiples

10x1=10

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10x4=40

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2 years ago

In the interval 0 x 360 find the values of x for which cos x =0.7252

Sergeeva-Olga [200]

Answer:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

Step-by-step explanation:

We have a positive value for the cosine of x, so we know that the value of x should be in the first quadrant (0 ≤ x ≤ 90) or in the fourth quadrant (270 ≤ x ≤ 360).

Now, let's find the value of x that gives cos(x) = 0.7252 using the inverse function of the cosine, that is, the arc cosine function.

The value of x can be calculated using:

$x = arccos(0.7252)$

Using this function in a calculator (you may find it as: $cos^{-1}(x)$ ), we have that:

$x_1 = 43.5145\°$

So this is the value of x in the first quadrant. To find the other value of x, in the fourth quadrant, that gives the same result, we just need to calculate 360° minus the value we found:

$x_2 = 360\° - 43.5145\° = 316.4855\°$

So the values of x are:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

7 0

3 years ago