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Alex73 [517]
3 years ago
6

Solve the equation for x 1/2(12x-10)=1/3(9+6x)

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

x =

Exact form:

- (63/2)

Decimal Form:

- 31.5

Mixed Numbers Form:

- (31 1/2)

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3000 times

First answer is 1200 and second is 0.4 so answer is 3000
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rewona [7]

Answer:

x = -68

Step-by-step explanation:

1) multiply the two members by 17

x = -68

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Geometry Help!
Elina [12.6K]

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  • x = 88.76°

Step-by-step explanation:

<u>Use the law of cosines:</u>

  • cos C = (a² + b² - c²)/(2ab)

<u>Apply to the given triangle and solve for x:</u>

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3 years ago
Where is 0.5 on a number line
Alexeev081 [22]
Right in the middle of 0 and 1
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3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x
frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx       (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units

The volume of the solid of revolution is approximately 8.06 cubed units

8 0
4 years ago
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