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adelina 88 [10]

3 years ago

9

The measurement of an angle is 40°, and the length of a line segment is 8 centimeters.

1 answer:

Tresset [83]3 years ago

7 0

1
a rhombus is defined as having 4 equal sides so if the measurement is 8 cm all sides will be 8 cm. a rhombus is a parallelogram so if one angle value is defined then the opposite angle is also 40 and the consecutive angles are equal to 140 degrees because consecutive angles in a parallelogram are congruent.

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The prime factors of a number are 2, 2, 2, and 5. What is the number?

fgiga [73]

Answer: 40

Step-by-step explanation:

Since 40 could be = 1 x 40, 2 x 20, 4 x 10, or 5 x 8.

The Factors of 40 will therefore be: 1, 2, 4, 5, 8, 10, 20, 40.

The Prime factor then is: 2, 2, 2, 5

Multiplying them together gives 40.

7 0

3 years ago

Solve the equation 6x + 12 = 4x - 18

kenny6666 [7]

Answer:

X = -15

Step-by-step explanation:

6X +12 = 4X -18

Subtract 4X from both sides

2X +12 = -18

Subtract 12 from both sides

2X = -30

Divide both sides by 2

X = -15

So basically just have the unknown on one side and normal numbers on the other. Make sure you do the same thing on both sides.

Mark me as brainliest if this helps!

4 0

3 years ago

Read 2 more answers

Nick and Adam workout together. Nick weighs 160 pounds and is gaining 3 pounds per week. Adam weighs 195 pounds and is losing ab

hoa [83]

Answer:

7 wks, 181 lbs

Step-by-step explanation:

160+3t=195-2t

160+5t=195

5t=35

t=7 weeks

160+3(7)=195-2(7)=181 pounds

5 0

3 years ago

What is the solution to the equation 1/2 x + 3 = 2/3 x + 1

Leni [432]

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$\frac{1}{2} x + 3 = \frac{2}{3} x + 1 \\$

Subtract sides 3

$\frac{1}{2} x + 3 - 3 = \frac{2}{3} x + 1 - 3 \\$

$\frac{1}{2} x = \frac{2}{3} x - 2 \\$

Multiply sides by 6

$6 \times \frac{1}{2} x = 6 \times \frac{2}{3} x + 6 \times ( - 2) \\$

$3x = 4x - 12$

Subtract sides 4x

$- 4x + 3x = - 4x + 4x - 12$

$- x = - 12$

Negatives simplifies

$x = 12$

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CHECK :

$\frac{1}{2} (12) + 3 = \frac{2}{3} (12) + 1 \\$

$6 + 3 = 8 + 1$

$9 = 9$

Thus the solution is correct .

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5 0

3 years ago

Please please help 100 points

stiks02 [169]

We're given

$\displaystyle \int_4^{-10} g(x) \, dx = -3$

which immediately tells us that

$\displaystyle \int_{-10}^4 g(x) \, dx = 3$

In other words, swapping the limits of the integral negates its value.

Also,

$\displaystyle \int_4^6 g(x) \, dx = 5$

The integral we want to compute is

$\displaystyle \int_{-10}^6 g(x) \, dx$

which we can do by splitting up the integral at x = 4 and using the known values above. Then the integral we want is

$\displaystyle \int_{-10}^6 g(x) \, dx = \int_{-10}^4 g(x) \, dx + \int_4^6 g(x) \, dx = 3 + 5 = \boxed{8}$

7 0

3 years ago