Answer:
if you were roundind I say the ten stays the same
Problem 10
<h3>Answer: 80 degrees</h3>
Work Shown: 80-0 = 80
You subtract the values on the protractor where the two angle arms line up.
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Problem 11
<h3>Answer: 45 degrees</h3>
Work Shown: 45-0 = 45
Same idea as problem 10
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Problem 12
<h3>Answer: 83 degrees</h3>
Work Shown: 128-45 = 83
Same idea as the others. The arm TS isn't fully on 130 degrees, and it's a bit short of it. It looks to be about 128 degrees or so.
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Problem 13
<h3>Answer: 35 degrees</h3>
Explanation: Luis forgot to subtract the value of each arm of the angle. So he should have done 80-45 = 35. The answer would be 80 degrees if arm TQ was at 0 degrees (so 80-0 = 80), but instead TQ is at 45 degrees.
You would combing like terms. In this case, it is 5/3v and 1/3v. So you would add them together to get 6/3v,or just 2 because 6 divided by 3 is 2. So now you have 2v+4=8.
Whole numbers start from 0 so i am guessing that you can find the decimal for 5/6=0.833 and then multiply .
