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3 years ago

Help me please ASAP!! :(

Mathematics

1 answer:

balu736 [363]3 years ago

4 0

Answer:

m= -1/7 (slope)

b= -1 (y inter)

Step-by-step explanation:

You might be interested in

The product of a number and four is subtracted from three to give forty seven

Ivan

Answer:

the number is -11

Step-by-step explanation:

let the number be written as x

so 3-4x=47

collect like terms

-4x=47-3

-4x=44

divide both sides by -4

-4x/-4=44/-4

x=-11

8 0

3 years ago

Sooooo, i spilled nail polish remover in my chrome book snd the keyboard is no longer working. also i'm on spring break tomorrow

k0ka [10]

Answer:

Oh snap TwT I wish U luck :3

Step-by-step explanation:

7 0

3 years ago

Divide:<br> 8.6) 3.440<br> short answer

ivanzaharov [21]

Answer:

well your answer will be 2.5

Step-by-step explanation:

2.5

5 0

3 years ago

Read 2 more answers

Find the distance between the two points.<br> (-1, -3), (1, 3)

allsm [11]

Answer:

d = 6.324555

Step-by-step explanation:

d=√1−(−1))^2+(3−(−3))^2

d=√(2)^2+(6)^2

d=√4+36

d=√40

d=6.324555

D=Distance*

4 0

3 years ago

Read 2 more answers

A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that $\pi = 0.08$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a p-value of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}$

$0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}$

$\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2$

$n = 996.3$

Rounding up:

A sample of 997 is needed.

3 0

3 years ago