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gizmo_the_mogwai [7]
3 years ago
11

Problem PageQuestion The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate paramet

er of per day. Find the half-life of this substance (that is, the time it takes for one-half the original amount in a given sample of this substance to decay).
Mathematics
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

8.55 days for a decay rate parameter of 8.1% per day

Step-by-step explanation:

Assuming a decay rate parameter of  8.1% per day

the general equation for radioactive decay is;

N = N₀e^(-λt)

x - decay constant (λ) - rate of decay 

t-  time 

N - amount remaining after t days , since we are calculating the half life, amount of time it takes for the substance to to be half its original value, its N₀/2

N₀ - amount initially present 

substituting the values 

N₀/2 = N₀e^(-0.081t)

0.5 = e^(-0.081t)

ln (0.5) = -0.081t

-0.693 = -0.081t

t = 0.693 / 0.081  = 8.55

half life of substance is 8.55 days 

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Step-by-step explanation:

According to the graph,

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3 years ago
Having troubles with inequalities.. 3.8x + 14.5 < 32
ryzh [129]
3,8x + 14.5 < 32\\&#10;3,8x
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What is 76.8/100 in grading. For instance is it an A,B,C,D,E etc.
ira [324]

Answer:

grading

A-1---80% AND ABOVE

A---70% AND ABOVE

SO 76.8/100=A

Step-by-step explanation:

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3 years ago
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Suppose you have 20 coins that total $4.some coins are nickles and sime are quarters .which of the following pairs of equations
Monica [59]
So 1 nickle=5 cents
1 quarter=25 sents

q=number of quarters
n=number of nickles so

total is
q+n=20
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SO THE 2 EQUATIONS WOULD BE
n+q=20
5n+25q=400

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subtract q from both sides
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add like terms
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4 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
4 years ago
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