Name 2 fractions that are greater than 1/2. Use benchmark fractions to help
1 answer:
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Answer:
This is possible.
Step-by-step explanation:
We can say that m<E=m<E, because of the Reflexive Property
Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.
With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).
Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), .
With this ratio, we can cross multiply to get the desired result
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Hope this helps with your RSM problem
Yup, i caught ya.
Answer:
A hole at x=-4.
Step-by-step explanation:
This is a fraction so we have to worry about division by zero.
The only time we will be dividing by 0 is when x+4 is 0.
Solving the equation
x+4=0 for x:
Subtract 4 on both sides:
x=-4
So there is either a vertical asymptote or a hole at x=-4.
These are the kinds of discontinuities we can have for a rational function.
If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.
If is is a vertical asymptote, x=-4 will make the top NOT zero.
Let's see what -4 for x in x^2+6x+8 gives us:
(-4)^2+6(-4)+8
16+-24+8
-8+8
0
Top and bottom are 0 when x=-4.
Let's see what happens after simplication.
We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.
So what 2 numbers together multiply to be 8 and add up to be 6.
I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.
We we able to cancel out that factor that was giving us x=-4 is a zero.
Therefore there is a hole at x=-4.