Answer:
we don't have the full answer sry.
Step-by-step explanation:
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
The answer is (3,2). I did this by drawing a graph, inserting the two midpoints you provided, and put in each potential midpoint, finding (3,2) is the only midpoint that connects to the line.
Answer:
169.56
Step-by-step explanation:
54*3.14 = 169.56
this is the answer on the test
If Lee starts with 100 pennies and adds groups of 10, the operation is addition. Since she does this 5 times, there is 5 different numbers Lee said.
100 + 10 = 110
110 + 10 = 120
120 + 10 = 130
130 + 10 = 140
140 + 10 = 150
Thus, all of the numbers she said were 110, 120, 130, 140, and 150.
Hope this helps! :)