Malika has $12 and spends $2 each choose relationship model that will reach zero in the same number of days as the scenario

The class scores of a history test have a normal distribution with a mean Mu = 79 and a standard deviation Sigma = 7. If Opal’s

storchak [24]

The value of z score for the history class test of Opal’s test score is negative one (-1).

<h3>What is normally distributed data?</h3>

Normally distributed data is the distribution of probability which is symmetric about the mean.

The mean of the data is the average value of the given data. The standard deviation of the data is the half of the difference of the highest value and mean of the data set.

The z score for the normal distributed data can be given as,

$Z=\dfrac{X-\mu}{\sigma}$

The mean value of the scores of history class is,

$\mu=79$

The standard deviation value of the scores of history class is,

$\sigma=7$

Here, the test score of the Opal’s is 72. Thus the z score for her test score can be given as,

$z=\dfrac{72-79}{7}\\z=-1$

Hence, the value of z score for the history class test of Opal’s test score is negative one (-1).

Learn more about the normally distributed data here;

brainly.com/question/6587992

6 0

3 years ago

What value of x is in the solution set of 3(х – 4) > 5х + 2?<br> 0—10<br> ОООО

MakcuM [25]

X < -7 hope this helps

4 0

3 years ago

30 POINTS AVAILABLE

kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

3 0

4 years ago

Ben made a model (shown below) of the square pyramid he plans to build when he grows up.

elena-s [515]

Answer:

$336 m^2$

Step-by-step explanation:

The surface area of a square pyramid is the sum of the area of the squared base + 4 times the area of each triangular face, therefore:

$A=A_b + 4A_t$

where:

$A_b=L^2$ is the area of the base, where

L is the length of the base

$A_t=\frac{1}{2}Lh$ is the area of each triangular face, where

h is the height of the face

Substituting,

$A=L^2+2Lh$

For the model in this problem,

L = 12

h = 8

Therefore, the surface area here is:

$A=12^2 +2(12)(8)=336$

4 0

3 years ago

Read 2 more answers

If Andy had an ending balance of $5600 and Charlie had an ending balance of $5624.32, what is the difference in their account ba

MakcuM [25]

The answer is 24.32 is the difference

8 0

3 years ago

Read 2 more answers