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fomenos
3 years ago
14

7 more than 11 times a number in algebraic expression

Mathematics
2 answers:
spayn [35]3 years ago
6 0
11x+7.  Adding 7 to eleven times a number                     
KiRa [710]3 years ago
6 0
11a plus 7 is your answer!!!
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With the symbols given us the symbol for ten and use the symbol for zero 3 times
5 0
3 years ago
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10n - 16 = 2(5n-8)] 15n + 25
Margaret [11]
The answer is 1.48226407 hope it helps
5 0
2 years ago
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I need to know which points go wj ere please
g100num [7]
The equations give you information as to where to plot points.

For y = -x + 1, you know the slope is -1, and the line intersects the y-axis at (0, 1). The y-axis is the vertical line; to plot (0, 1), find 1 on the vertical line and mark it. Now, the slope is -1; that means the line will slope downwards. To plot more points, count 1 unit down from (0, 1) and 1 unit to the right. You should end up at (1, 0).Connect those and you have a line.

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I hope this helps.
3 0
3 years ago
Find sin(a+B)
diamong [38]

Answer:

Cos A=5/13

we have

Cos² A=1-Sin ²A

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A=\sqrt{144/169}=12/13

again

Tan B=4/3

P/b=4/3

p=4

b=3

h=\sqrt{3²+4²}=5

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>

<u>n</u><u>o</u><u>w</u><u> </u>

<u>substitute</u><u> </u><u>value</u>

<u>Sin(A+B):</u>12/13*3/5+5/13*(-4/5)=36/65-4/13

<u>=</u><u>1</u><u>6</u><u>/</u><u>6</u><u>5</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>

6 0
2 years ago
Charles has 2 2/3 ounces of seeds. He needs 4 4/5 ounces in order to complete the garden. How much more seeds he need?
yawa3891 [41]

Answer:

Charles need 3\frac{1}{5} more ounces of seeds.

Step-by-step explanation:

Given that:

Quantity of seeds Charles has = 2\frac{2}{3} = \frac{8}{3} ounces

Quantity of seeds Charles need = 4\frac{4}{5} = \frac{24}{5} ounces

Let,

x be the number of remaining seeds Charles need.

x = Seeds needed - Seeds Charles already have

x = \frac{24}{5}-\frac{8}{3}

x = \frac{72-24}{15}

x = \frac{48}{15}

x = \frac{16}{5}

x = 3\frac{1}{5} ounces

Hence,

Charles need 3\frac{1}{5} more ounces of seeds.

5 0
3 years ago
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