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Nimfa-mama [501]
3 years ago
6

Prove this identity sin^2θcsc^2θ=sin^2θ+cos^2θ by simplifying both sides of the equation.

Mathematics
2 answers:
Gwar [14]3 years ago
8 0

\bf \begin{array}{rllll} sin^2(\theta )csc^2(\theta )&=&sin^2(\theta )+cos^2(\theta )\\\\ ~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \cdot \cfrac{1^2}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }&=&1\\\\ 1^2&=&1\\ 1&=&1 \end{array}

Zanzabum3 years ago
8 0

Answer:

Step-by-step explanation:

sin^2 \theta csc^2 \theta=sin^2\theta+cos^2 \theta\\L.H.S.=sin ^2\theta cos^2\theta=\frac{sin^{2}\theta }{sin ^{2}\theta } =1\\R.H.S.=sin^{2} \theta+cos^{2} \theta=1\\L.H.S.=R.H.S

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6. Describe the end behavior and determine
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Answer:

6. an odd-degree polynomial function.

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Step by step explanation;

6. The graph represent an odd-degree polynomial function.

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7.

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Let=w=x  , l=x+10  and A=144 in² then;

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(x+5)²=169.......................square root the right-hand side

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Length =x+10=8+10=18 inches

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