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3 years ago

What is the answer to this in degrees

Mathematics

2 answers:

makkiz [27]3 years ago

6 0

Answer: 155°

Step-by-step explanation:

BC is the same as AD

sasho [114]3 years ago

4 0

Answer:

155

Step-by-step explanation:

As the diagram shows, it looks the same as the other side. In, that case it would be the same so 155.

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Write an explicit formula for an, the nth term of the sequence 24, 28, 32, ....

noname [10]

Answer:

Given the sequence 20, 24, 28, 32, 36, . . . find the 60th term.

------

nth term pattern: a(n) = 20 + (n-1)4

60th term: a(60) = 20 + 59*4 = 256

Step-by-step explanation:

3 0

2 years ago

The consistency of repeated measurement, often expressed by the number of decimal places, is called a measurement's ______.

melisa1 [442]

The consistency of repeated measurement, often expressed by the number of decimal places, is called a measurement's precision.

7 0

3 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$