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kirill115 [55]
3 years ago
5

What is the answer to this in degrees

Mathematics
2 answers:
makkiz [27]3 years ago
6 0

Answer: 155°

Step-by-step explanation:

BC is the same as AD

sasho [114]3 years ago
4 0

Answer:

155

Step-by-step explanation:

As the diagram shows, it looks the same as the other side. In, that case it would be the same so 155.

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Write an<br> explicit formula for an, the nth term of the sequence 24, 28, 32, ....
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Answer:

Given the sequence 20, 24, 28, 32, 36, . . . find the 60th term.

------

nth term pattern: a(n) = 20 + (n-1)4

60th term: a(60) = 20 + 59*4 = 256

Step-by-step explanation:

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2 years ago
The consistency of repeated measurement, often expressed by the number of decimal places, is called a measurement's ______.
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The consistency of repeated measurement, often expressed by the number of decimal places, is called a measurement's precision.
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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0
3 years ago
69108 what is this number written in standard form
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Sixty-nine thousand, a hundred and eight?
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3 years ago
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Find the output values of the exponential function g(x) = 4,096x for x = 0, 0.25, 0.50, 0.75, and 1.
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Hello,g(x)=4096^xg(0)=1g(0.25)=(2^12)^1/4=2^(12/4)=2^3=8g(0.50)=(2^12)^(1/2)=2^6=64g(0.75)=(2^12)^(3/4)=2^9=512g(1)=4096^1=4096.

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3 years ago
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