Answer:
- Cos 45=6/x
x=6/cos 45=6√2
x=6√2
tan 45=y/6
y=tan45 ×6
y=6
2.
sin 60=y/10
y=sin60×10
y=5√3
again
Cos 60=x/10
x=½×10
x=5
3.
Sin 45=x/5
x=1/√2×5 or
x=5√2/2
again
y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]
4.
Sin 30=8/x
½×x=8
x=8*2
x=16
again
cos 30= y/x
√3/2×16=y
y=8√3
5.
sin 60=7/x
x=7/[√3/2]
x=14/√3 or 14√3/3
again
cos 60=y/x
½×14√3/3=y
7√3/2=y
y=7√3/2
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Answer:
3.58
Step-by-step explanation:
Given :
y = 2x + 4 -------- eq1
y = 2x - 4 -------- eq2
sanity check : both equations have same slope, so we can conclude that they are both parallel to one another.
Step 1: consider equation 1, pick any random x-value and find they corresponding y-value. we pick x = -2
This gives us y = 2(-2) + 4 = 0
Hence we get a point (x,y) = (-2,0)
Step 2: express equation 2 in general form (i.e Ax + By + C = 0)
y = 2x-4 -------rearrange---> 2x - y -4 = 0
Comparing with the general form, we get A = 2, B = -1, C = -4
Recall that the distance between 2 parallel lines is given by the attached formula (see attached picture).
substituting the values for A, B, C and (x, y) from the previous step:
d = | (2)(-2) + (-1)(0) + (-4) | / √(2² + (-1)²)
d = | -4 + 0 - 4 | / √(4 + 1)
d = | -8 | / √5
d = 8 / √5
d = 3.5777
d = 3.58 (rounded 2 dec. pl)
The answer should be 16.26