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NikAS [45]
4 years ago
10

What is the equation of the line that passes through the point (-6,-8) and has a slope of 1/3

Mathematics
1 answer:
Ugo [173]4 years ago
4 0

Answer:

y = 1/3 x -5

Step-by-step explanation:

We can write the equation of a line as

y = mx+b

where m is the slope and b is the y intercept

y = 1/2x +b

Substitute the point into the equation

-8 = 1/2 (-6) +b

-8 = -3 +b

Add 3 to each side

-8+3 = -3 +3 +b

-5 = b

y = 1/3 x -5

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Answer:

y = 5x + 8

Step-by-step explanation:

If you want to find a equation parallel to the line given, you need to know the slope of the line given. Remember that parallel lines have the same slope.

5x - y = 4 and solving for y:

-y = -5x + 4 and solving for positive y:

y = 5x - 4

So the slope of that line is 5. We will use that along with the coordinate given to us to write the equation first in point-slope form then in slope-intercept:

y - (-2) = 5(x - (-2)) and

y + 2 = 5(x + 2) and

y + 2 = 5x + 10 so

y = 5x + 8

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3 years ago
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Ymorist [56]
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