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3 years ago

Find the range for this data set {3,5,7, 3, 6, 4, 8, 6, 9, 5) *

Mathematics

2 answers:

AVprozaik [17]3 years ago

6 0

Step-by-step explanation:

you take the highest value and subtract it from the lowest value.

OverLord2011 [107]3 years ago

3 0

Answer:

Step-by-step explanation:

9-3=6

You might be interested in

On the number line below, length <br> AB= {?}

SVEN [57.7K]

Answer:

29 units

Step-by-step explanation:

The length of a segment of a number line is the difference of the coordinates of the end points:

45 -16 = 29

3 0

3 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

WILL GIVE BRAINLIEST

Alex

Answer:

Step-by-step explanation:

(3.14)(15*15)(315)=222548

5 0

3 years ago

The circumference of the target above is 6,895.4400000000 mm.

Sergio039 [100]

Diameter of the target is 2196 mm

Step-by-step explanation:

We are given Circumference of target = 6,895.4400000000 mm.

We need to find the diameter of target.

The formula used is:

$C= 2\pi r$

Putting values:

$C=2\pi r\\6,895.4400000000=2*3.14*r\\6,895.4400000000=6.28*r\\r=\frac{6,895.4400000000}{6.28} \\r=1098\,\,mm \\$

We know that $Diameter = 2*radius$

So, Finding Diameter:

$Diameter = 2*radius\\Diameter = 2*1098\\Diameter = 2196\,\,mm$

So, Diameter of the target is 2196 mm

Keywords: Circumference

Learn more about Circumference at:

#learnwithBrainly

4 0

3 years ago

Simplify the following polynomial expression

Juli2301 [7.4K]

Distribute the negative sign

$7x^2-3x-6$

Combine like terms

-9x^2 + 7x^2 = -2x^2

9x - 3x = 6x

13 - 6 = 7

$-2x^2 +6x + 7$

<u>Answer</u>

$-2x^2 +6x + 7$

3 0

3 years ago