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Nitella [24]
3 years ago
6

What is an equation of the line that passes through the points (−5,−7) and (5,1)?

Mathematics
1 answer:
____ [38]3 years ago
6 0

Answer:

y = \frac{4}{5} x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 5, - 7) and (x₂, y₂ ) = (5, 1)

m = \frac{1+7}{5+5} = \frac{8}{10} = \frac{4}{5}, thus

y = \frac{4}{5} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (5, 1), then

1 = 4 + c ⇒ c = 1 - 4 = - 3

y = \frac{4}{5} x - 3 ← equation of line

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What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11?
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Answer:

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Step-by-step explanation:

When you solve for y, the slope of the line is the x-coefficient. For the given line, that is ...

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