Answer:
Closed and Bounded.
Step-by-step explanation:
Hi there!
1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

Since every quadratic root are defined for values
0 then, this help us to understand that we need calculate what interval this Domain is:

![D=[-2,2]](https://tex.z-dn.net/?f=D%3D%5B-2%2C2%5D)
2) Graphically speaking, the domain is closed. For the values -2 and 2 are included, and bounded.
Bounded functions have all of their points contained by some circle origin centered. Check it out below.
Answer:
Hello,
Step-by-step explanation:
Area of the sphere:

Volume of the sphere:



PEMDAS
the first thing is multiply or distribute
a(b+c)=ab+ac
8(t+2)=8t+16
-3(t-4)=-3t+12
6(t-7)=6t-42
the equation comes out to
8t+16-3t+12=6t-42+8
add like terms
5t+28=6t-34
subtract 5t from both sides
28=t-34
add 34 to both sides
62=t
2(x - 5)² + 13 = 31
2(x - 5)(x - 5) + 13 = 21
2(x(x - 5) - 5(x - 5)) + 13 = 21
2(x(x) - x(5) - 5(x) + 5(5)) + 13 = 21
2(x² - 5x - 5x + 25) + 13 = 21
2(x² - 10x + 25) + 13 = 21
2(x²) - 2(10x) + 2(25) + 13 = 21
2x² - 20x + 50 + 13 = 21
2x² - 20x + 63 = 21
<u> - 21 - 21</u>
2x² - 20x + 42 = 0
2(x²) - 2(20x) + 2(21) = 0
<u>2(x² - 20x + 21)</u> = <u>0</u>
2 2
x² - 20x + 21 = 0
x = <u>-(-20) +/- √((-20)² - 4(1)(21))</u>
2(1)
x = <u>20 +/- √(400 - 84)</u>
2
x = <u>20 +/- √(316)
</u> 2
x = <u>20 +/- 2√(79)</u>
2
x = 10 <u>+</u> √(79)
x = 10 + √(79) U x = 10 - √(79)
<u />
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