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lawyer [7]
4 years ago
11

Solve the problem X/5 +4=17

Mathematics
2 answers:
ioda4 years ago
4 0

Answer:

x = 65

Step-by-step explanation:

X/5 +4=17

Subtract 4 from each side

X/5 +4-4=17-4

x/5 = 13

Multiply each side by

x/5 *5 = 13*5

x = 65

RideAnS [48]4 years ago
3 0

Answer:

x=65

Step-by-step explanation:

x/5+4=17

solve for x by simplifying for both sides of the equation, then isolate the variable. x=65

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A cone has a lateral area of 108 in2 and a base area of 48 in2. What is the surface area of the cone? A. 60 in2 B. 140 in2 C. 12
Andrei [34K]
Based on the given data, the following formula will be useful;
Area of the base, A = pi*r^2
Lateral Area, A(l) = pi*r*sqrt of h^2 + r^2
Surface Area, A(s) = pi*r*(r+sqrt of h^2 + r^2)
Based on the given area of the base, the radius can be calculated and is equal to 3.9088 in. Based on the given lateral area, the h or the lateral edge can be calculated and is equal to 7.8785 in. Given all the information needed, and directly substituting to the above formula for surface area, SA is equal to 156 in^2 (option D)
5 0
3 years ago
Can someone explain end behaviors and answer this question?
Luda [366]

Answer:

End behaviors are basically what the function looks like as it ends.

as x approaches positive infinity (the sideways 8) its increasing.

for the picture i believe the answer is C.

Step-by-step explanation:

basically because when you look at where the negatives are they continue which means it’s -infinity and so as the function approaches -infinity it’s x —> positive infinity and same thing for as x approaches positive infinity.

5 0
3 years ago
6. Let A and B be nxn matrices . Compute (A + B) (A + B). Explain all steps.
Pie

Answer:

(A+B)(A+B)=A.A+B.A+A.B+B.B

Step-by-step explanation:

Given that matrices A and B are nxn matrices

We need to find (A+B)(A+B)

For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.

We know that that in matrices AB is not equal to BA.

Now find  

(A+B)(A+B)=A.A+B.A+A.B+B.B

So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.

So (A+B)(A+B)=A.A+B.A+A.B+B.B

4 0
3 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
Think of a number . Multiply by 6 and add 5 is 11.Frame an equation and<br><br>solve .
motikmotik

Answer:

x=1

Step-by-step explanation:

6x+5=11

6x=11-5

6x=6

x=1

8 0
3 years ago
Read 2 more answers
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