SinB = cosC = AC / BC = 8/10 = 4/5;
tgB = ctg C = AC/AB = 8/6 = 4/3, because we use T. Pitagora for calculating AB;
sinC = cosB = AB/ BC = 6/10 = 3/5;
tgC = ctgB = AB/ AC = 6/8 = 3/4.
We have been given graph of circle V with radius 14 feet. We are asked to find the area of the circle V.
We will use area of circle formula to solve our given problem.
, where r represents radius of circle.
Upon substituting in above formula, we will get:
Therefore, the area of the circle V is square feet and option 'c' is the correct choice.
Answer:
602.88cm²
Step-by-step explanation:
Find the image of the cylinder attached
Surface area of a cylinder = A=2πrh+2πr²
r is the radius = 4cm
Height h = 20cm
Substitute
A = 2πr(r+h)
A = 2π(4)(4+20)
A = 8π(24)
A = 192π
A = 192(3.14)
A = 602.88cm²
Hence the surface area of the cylinder is 602.88cm²
Answer: 17 -3n
Explanation:
In the given arithmetic progression 20,17,14,11,8....
first term that is a = 20
common difference that is d= a2-a1 = 17-20 = -3
let n is the nth term
= a+(n-1)d
substituting the values of first, common,difference and n
=20+(n-1) (-3)
= 20 -3n+3
=23 -3n