Question

A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a depth that is LaTeX: 3\frac{1}{4}3 1 4feet below where it was at 1: 00 p.M. What rational number represents the position of the fish with respect to the water's surface at 4:00 p.M.?

Answer 1

Answer:

$\frac{23}{4}$ feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 $\frac{1}{2}$ feet

                                                                             =   $\frac{5}{2}$ feet

The depth of the fish to its initial position at 4:00 pm = 3 $\frac{1}{4}$ feet

                                                                              = $\frac{13}{4}$ feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

                                        =  $\frac{5}{2}$ + $\frac{13}{4}$

                                        = $\frac{10 + 13}{4}$

                                         = $\frac{23}{4}$

The position of the fish with respect to the water's surface at 4:00 pm is $\frac{23}{4}$ feet.