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Natalka [10]
3 years ago
15

**PLEASE HELP** What is the length of the altitude of the equilateral triangle below?

Mathematics
1 answer:
charle [14.2K]3 years ago
5 0
For any 30-60-90 triangle:
Let the length of hypotenuse = x
∴ The leg which faces the angle 30 = (1/2) x 
And the leg which faces the angle 60 = (√3/2) x 
So, The ratio between two legs will be 
= (1/2) x : (√3/2) x     ⇒⇒⇒⇒ divide over x
= 1/2  :  √3/2             ⇒⇒⇒⇒ multiply by 2
= 1  :  √3

Or the ratio will be

= (√3/2) x  :  (1/2) x    ⇒⇒⇒⇒ divide over x
= √3/2  :  1/2             ⇒⇒⇒⇒ multiply by 2
=  √3  :  1
==============================

The correct answer will be option B only

B.  1 : √3







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25 dobles y 42 sencillas

Step-by-step explanation:

25 x 2 = 50 camas + 42 = 92

y 25 habitaciones dobles + 42 sencillas = 67

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What is 5(n-1)=2(n-4)-6
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Step-by-step explanation

6n - 6 = 2 (n+1)

Simplify 2 (n+1)

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Move all terms related to n to the left side of the equation

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Move all terms not related to n to the right side of the equation

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Which graph shows the solution to the following equation?<br><br> 2x-5/x^2 = -4
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Step-by-step explanation:

4 0
3 years ago
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Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

3 0
3 years ago
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