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svetlana [45]
3 years ago
12

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

e highest bid in excess of $9,500 will be accepted. Assume that the competitor's bid x is a random variable that is uniformly distributed between $9,500 and $14,700. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?
Mathematics
1 answer:
Karolina [17]3 years ago
5 0

Answer:

Probability (bid accepted) = 0.48

Step-by-step explanation:

Probability density is given byF(y)= 1/(b-a)

a=9500

b= 14700

F(y)= 1/(14700-9500) =1/5200=0.00019

Probability (bid accepted)= (12000-9500)÷1/5200

P( bid accepted) = 2500×0.00019=0.475 approximately 0.48

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Answer:

The width of the rectangle is 2.3 m

Step-by-step explanation:

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Now, we are given that the area of a rectangle is 12.65 m^2 and the length measures 5.5 m

So the width is given as:

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3 years ago
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2 years ago
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Answer:

Step-by-step explanation:

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What is the equation of a line perpendicular to:
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2 years ago
Which system is equivalent y=-2x^2 y=x-2
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The wording of your question suggests that there were answer choices.  Mind sharing them?

The system   <span>y=-2x^2 y=x-2 would be best written as:

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