All categories

2 years ago

Y=mx b when solving for b

Mathematics

1 answer:

BigorU [14]2 years ago

7 0

Y = mx + b.....subtract mx from both sides
y - mx = b

You might be interested in

Sketch the parabola y = x2 + 4x – 5.

Daniel [21]

Step-by-step explanation:

y=(x+5)(x-1)

y=-5 x=0

y=0. x=-5

y=0 x=1

now you got the points so graph will be like

5 0

2 years ago

Pls help! will mark branliest!!! :)

Ket [755]

The area of the house is the amount of space on the house.

The length of the addition is x + 20
The area of the original house is $x^2 + 30x + 200$

<h3>The length of the addition</h3>

The area of the addition is given as:

$Area = x^2 + 10x - 200$

Expand

$Area = x^2 + 20x - 10x - 200$

Factorize

$Area = x(x + 20) - 10(x + 20)$

Factor out x + 20

$Area = (x -10)(x + 20)$

The width of the addition is x - 10.

Hence, the length of the addition is x + 20

<h3>The area of the original house</h3>

The dimension of the original house is

x + 20 by x + 10

So, the area is:

$Area =(x + 20)(x + 10)$

Expand

$Area =x^2 + 20x + 10x + 200$

This gives

$Area =x^2 + 30x + 200$

Hence, the area of the original house is $x^2 + 30x + 200$

Read more about areas at:

brainly.com/question/24487155

8 0

2 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

Which of the following is the equation of a line perpendicular to the line y = -10x + 1, passing through the point (5,7)?

Viktor [21]

Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
$\frac{y-5}{x-7} = \frac{1}{10}$
y-5= $\frac{1}{10} {x-7}$
y-5= $\frac{1}{10} x- \frac{7}{10}$
y= $\frac{1}{10} x- \frac{43}{10}$

6 0

3 years ago

Read 2 more answers

Convert 15 m² to in². How many square inches are in 15 square meters?

Sati [7]

Answer:

23250

Step-by-step explanation:

23250 square inches are in 15 square meters.

3 0

2 years ago