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harkovskaia [24]
4 years ago
15

How many revolutions must be made by a wheel of diameter 2.8m in order to cover a distance of 484km?

Mathematics
1 answer:
arlik [135]4 years ago
5 0
<h2>Answer :</h2>

A wheel is a circle.

Given diameter of wheel = 2.8 m

Then radius of the wheel = 2.8/2 = 1.4 m

Now we know that , circumference of circle =2\pi r

<h3>Then, </h3>

Circumference of wheel = 2 × 22/7 × 1.4

Circumference of wheel = 8.8 m

<u>From the above we can conclude that ;</u>

1 revolution = 8.8 m

x revolution = 484 km = 484000 m

<h3>Thus, </h3>

x =  \frac{1}{8.8}  \times 484000 \\  \\ x = 55000

<h3>Therefore, total of 55,000 revolutions are made by the wheel.</h3>
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Answer:

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Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let \mu be the random variable that follows a Poisson distribution, then mean \mu = \dfrac{10}{500}= 0.02

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Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

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P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]

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the number of workers because d=260w.

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<h3>Answer:</h3>

\boxed{\bold{a_n = a_{n-1} -0.8}}

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