<h3>
Answer: 5</h3>
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Work Shown:
x^2 - 5x + 1 = 0
x^2 + 1 - 5x = 0
x^2 + 1 = 5x
(x^2 + 1)/x = 5 .... where x is nonzero
(x^2)/x + (1/x) = 5
x + (1/x) = 5
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An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.
In this case,
p = (5 + sqrt(21))/2
q = (5 - sqrt(21))/2
Answer:
Grampy
Step-by-step explanation:
money cards
Grampy= $12 4 packs
James= $28 7 packs
12*2= 24 dollars and 8 packs
while James payed 28 dollars for 7 packs
So Grampy got a better deal.
Answer:
k = -6/35
Step-by-step explanation:
To make the function continuous
kx^2 = x+k
These must be equal where the function is defined for two different intervals
This is at the point x=-6 so let x=-6
k(-6)^2 = -6+k
36k = -6+k
Subtract k from each side
36k-k = -6+k-k
35k = -6
Divide by 35
35k/35 = -6/35
k = -6/35
Answer:
what is the question ? but i dont know ans
Answer:
B. 
Step-by-step explanation:
Given:
(2, 4) and (2, -9)
Required:
Midpoint of the vertical line with the above endpoints
Solution:
Apply the midpoint formula, which is:
Where,
(2, 4) = (x_1, y_1)
(2, -9) = (x_2, y_2)
Plug in the values into the equation:
