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V125BC [204]
3 years ago
11

Four minus x , multiplied by 15

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
It would be 4-15x
sorry if not
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about 60 miles(97 km) west of denver Colorado..i think this is helpful.

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Z -7, when z=6 PLS HELP MY I AM NOT SURE IF I DID IT RIGHT I HAVE TO TURN THIS IN TOMORROW
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Z-7

6-7

-1

Step-by-step explanation:

we have to replace the value of Z and then subtract by seven.

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out of a group of zebras 6/5 times the square root of the number of zebras are playing on the shore of the tank remaining six ar
MatroZZZ [7]

Answer:

Step-by-step explanation:

(6/5)√x = x - 6

(36/25)x = x² - 12x + 36

0 = x² - 13.44x + 36

x = (13.44 ± √(13.44² - 4(1)(36))) / (2(1))

x = (13.44 ± 6.052569702...) / 2

x = 3.69371... zebras

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x = 9.74628... zebras

In either case we have some odd fractions of zebras hanging around. This makes me highly suspect that the question is misreported

3 0
2 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
At Smith's Grocery Store, almonds are on sale for $3.14 per pound. Walnuts are on sale for $2.65 per pound. How much more per po
eimsori [14]

Answer:

$0.49is the answer

Step-by-step explanation:

3.14-2.65=0.49

3 0
2 years ago
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