Given :-
- 12 workers can do a piece of work in 20 days .
To Find :-
- How many workers should be added to complete the work in 16 days ?
Solution :-
According to the question ,
→ In 20days 12 workers can do a piece of work.
→ In 1day 12*20 workers can do that work
( Less days , more workers )
→ In 16 days 12*20/16 = 15 workers can do the work.
So 15 -12 = 3 workers should be added to complete the work.
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>3 </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>
We will see that f'(x) > 0, which means that f(x) is an increasing function.
<h3>
How to prove that the function is increasing?</h3>
For any function f(x), if f'(x) > 0, then f(x) is increasing for any value of x.
Here we have the cubic function:
f(x) = x³ + 4x
If we differentiate this, we get:
f'(x) = df(x)/dx = 3x² + 4.
And notice that x² is always positive, then f'(x) > 0, which means that f(x) is an increasing function.
If you want to learn more about cubic functions:
brainly.com/question/20896994
#SPJ1
Answer:
a)
T` {-4,-2}
R` {2,8}
S` {-9,4}
Step-by-step explanation:
x, y → y,x
<span>C.-8+(8+7)=(-8+8)+7.</span>
Answer:
y = 0.5cos(4(x+π/2)) -2
Step-by-step explanation:
The centerline of the oscillation is at -2, so only the 2nd and 4th choices are viable.
The multiplier of x is computed from (2π)/period. One period is π/2, so the multiplier of x is ...
... 2π/(π/2) = 4 . . . . . matching the 2nd selection.
The horizontal offset in the second equation (π/2) is of no consequence, as it is one full period of the function.
The peak-to-peak amplitude of the oscillation is 1 unit, so the multiplier of the cosine function (which usually has a peak-to-peak value of 2 units) is 0.5. Every offered answer has that characteristic.
The appropriate choice is the 2nd one:
... y = 0.5cos(4(x+π/2)) -2
