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aleksley [76]
3 years ago
6

The probability distribution shows the probability of the number of prior car accidents for 100 individuals that have put in a c

laim with an insurance company following an accident.
What is the probability that an individual among these 100 represented had less than 3 prior car accidents?

Enter your answer, as a decimal

Mathematics
2 answers:
krok68 [10]3 years ago
6 0
Answer: 60% of the people in the survey have had less than 3 accidents.

If we are looking for the amount that is less than 3 accidents, we have to add up the percent for the people that had 1 or 2 accidents.

0.35 for 2 accidents plus 0.25 for 1 accident equal 0.6 for both (or 60%).
lara31 [8.8K]3 years ago
4 0

Answer:

The required probability is 0.6.

Step-by-step explanation:

Given : The probability distribution shows the probability of the number of prior car accidents for 100 individuals that have put in a claim with an insurance company following an accident.

To find : What is the probability that an individual among these 100 represented had less than 3 prior car accidents?

Solution :

According to the given pictorial graph of prior car accidents,

The probability represented had less than 3 prior car accidents is 1 and 2.

The probability represented had less than 3 prior car accidents 1 is 0.25.

The probability represented had less than 3 prior car accidents 2 is 0.35.

Total probability represented had less than 3 prior car accidents is 0.25+0.35=0.6.

Therefore, The required probability is 0.6.

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A truck is stopped at a stop sign. After realizing the driver should go straight, he accelerates the truck at a constant rate of
san4es73 [151]

Answer:

v = 33.8 m/s

Step-by-step explanation:

Given that,

The initial velocity of the truck, u = 0

Acceleration of the truck, a = 3.6 m/s²

Time, t = 9.4 s

We need to find the car's final velocity. Let v is the final velocity.

Using equation of kinematics as follows :

v = u +at

Since, u = 0

a=3.6\times 9.4\\\\v=33.8\ m/s

Hence, the final velocity of the car is 33.8 m/s.

3 0
4 years ago
Can someone help me do 8 divided by 5.5?? Thanks!!
Viktor [21]
First you put 8 on the inside of a house and 5.5 on the outside. Then you take the 5.5 and see how many times it can go in 8 with out going over, in this case its once. So take 5.5 and subtract it under the 8. Since you used up the whole number, you have to put a decimal now, so put a decimal on the right side of the 1 on top of the house. Then, add a 0 next to the 8 and put it next to the answer of 8-5.5, which is 2.5, and now 25, the zero moving the number to the left once. Now you find out how many times 5.5 goes into 25, which is 4, adding that next to the decimal on top of the house. Now again, subtract 22, which is 4 x 5.5, from 25. Then add a zero, making 3, now 30.Now find how many times 5.5 goes into that, and it is 5. This 4 and 5 pattern will go on forever, so over the 45 in your answer 1.45, put a line. Like this      __
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4 0
3 years ago
2. Eliminate the y in the following system of equations. What is the result when you add the two equations?
lisabon 2012 [21]

Answer:

B

Step-by-step explanation:

3x - 2y = 8 → (1)

x + y = 6 → (2)

Multiplying (2) by 2 and adding to (1) will eliminate y

2x + 2y = 12 → (3)

Add (1) and (3) term by term to eliminate y

(3x + 2x) + (- 2y + 2y) = (8 + 12) , that is

5x + 0 = 20

5x = 20 → B

4 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms oc
Anit [1.1K]

Answer:

a)\hat \sigma^2 =s^2 =30^2 = 900

b) 567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

c) 23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

Step-by-step explanation:

Data given and notation

s=30 represent the sample standard deviation

\bar x=290 represent the sample mean

n=20 the sample size

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Part a

The best point of estimate for the population variance is the sample variance, so on this case:

\hat \sigma^2 =s^2 =30^2 = 900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,19)" "=CHISQ.INV(0.95,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma \leq \frac{(19)(30)^2}{10.117}

567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

Part c

In order to find the confidence interval for the deviation we just need to take the square root for the interval of the variance, and we got:

23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

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